Question

good morning!
solve this question

Answer 1

Answer:

(2 - a^2)^(3/2)

Step-by-step explanation:

For the better understanding, I am writing θ as A.

$Given:sec A+tan^3A*cosecA$

$=secA(1+tan^3A*\frac{cosecA}{secA})$

$=secA(1+tan^3A * \frac{\frac{1}{sinA}}{\frac{1}{cosA}})$

$=secA(1+tan^3A*\frac{cosA}{sinA})$

$=secA(1+tan^3A*cotA)$

$=secA(1+tan^3A*\frac{1}{tanA})$

$=secA(1+tan^2A)$

$=secA(sec^2A)$

$=sec^3A$

$=(sec^2A)^{\frac{3}{2}}$

$=(1+tan^2A)^{\frac{3}{2}}$

$=(1+1-a^2)^{\frac{3}{2}}$

$=\boxed{(2-a^2)^{\frac{3}{2}}}$

Hope it helps!

Answer 2

Answer:

sorry i cant see this