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Answer 1

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Answer 2

Step-by-step explanation:

$\sf |x| \:is\: the\: modulus \:function \\ \\ \sf if \: |x| = a \:then\:. x = a \: \: \: \: \: or \: \: \: \: \: x = - a \\ \\ \sf (i) | 3x - 5 | = 1 \\ \\ \sf 3x - 5 = 1 \: \: \: \: \: or \: \: \: \: \: 3x - 5 = -1 \\ \\ \sf 3x = 6 \: \: \: \: \: or \: \: \: \: \: 3x = 4 \\ \\ \sf x = 2 \: \: \: \: \: or \: \: \: \: \: x = \frac{4}{3} \\ \\ \sf (ii) |7-2x| = 5 \\ \\ \sf 7 - 2x = 5 \: \: \: \: \: or \: \: \: \: \: 7 - 2x = - 5 \\ \\ \sf 2x = 2 \: \: \: \: \: or \: \: \: \: \: 2x = 12 \\ \\ \sf x = 1 \: \: \: \: \: or \: \: \: \: \: x = 6 \\ \\ \sf |\frac{8-x}{2}| =2 \\ \\ \sf \frac{8-x}{2} = 2 \: \: \: \: \: or \: \: \: \: \: \frac{8-x}{2} = - 5 \\ \\ \sf 8 - x = 4 \: \: \: \: \: or \: \: \: \: \: 8 - x = -10 \\ \\ \sf x = 4 \: \: \: \: \: or \: \: \: \: \: x = 18 \\ \\ \sf | 5 + \frac{x}{4}| = 5 \\ \\ \sf 5 + \frac{x}{4} = 5 \: \: \: \: \: or \: \: \: \: \: 5 + \frac{x}{4} = - 5 \\ \\ \sf \frac{x}{4} = 0\: \: \: \: \: or \: \: \: \: \: \frac{x}{4} = - 10 \\ \\ \sf x = 0 \: \: \: \: \: or \: \: \: \: \: x = - 40$

❣️NIRANJAN 45❣️