Good morning.
This question is made by me.
Solve the equation and find the value of x.
![\sf{2}^{x} + {3}^{x} + {4}^{x} = 1299 \sf{2}^{x} + {3}^{x} + {4}^{x} = 1299](https://tex.z-dn.net/?f=+%5Csf%7B2%7D%5E%7Bx%7D++%2B+%7B3%7D%5E%7Bx%7D++%2B++%7B4%7D%5E%7Bx%7D++%3D+1299)
Solve it if you can.
Plz don't spam. It's my request to everyone.
Answers
Answered by
5
Answer:
X=5
Step-by-step explanation:
I did trial and error. I first put 7 but its too high so i start with 3 then 4 then 5 is the correct answer
Answered by
0
Step-by-step explanation:
X=5
This is the answer....
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