Question

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Jo sbse pehle solve karega usko milenge meri taraf se 16 rupees.... Question no-34....plzz



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Answer 1

P(of getting a prime no on each dice) = 1 / 4

P(of getting a total of 9 or 11) = 1 / 6

Step-by-step explanation:

Total no of possible outcomes in two dice = 6 * 6 = 36

Sample Space:

Possible outcomes for a prime no = (2,2), (2, 3), (2, 5), (3, 2), (3, 3),(3, 5), (5, 2), (5, 3), (5,5)

There are total 9 possible outcomes.

$\boxed{\text{P(E)=number of outcomes / total number of outcomes}}$

P(E) = 9 / 36

= 3 / 12

= 1 / 4

(ii)Favorable outcomes when sum of numbers are 9 or 11 are (3, 6), (4, 5), (5, 4), (5, 6),(6, 3), (6,5),

There are total 6 possible outcomes.

P(E) = 6 / 36

= 1 / 6

Answer 2

Answer:

probability of getting prime number is 1/4

probability of getting 9or 11is 1/6