Question

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Derive the third equation of motion...

Answer 1

Answer:

$v^{2}=u^{2}+2as$

Step-by-step explanation:

$From \ first \ equation \ of \ motion \ we \ have \ v=u+at\\\\Now \ squaring \ on \ both \ side\\\\v^{2}=(u+at)^{2} \\\\v^{2}=u^{2}+a^{2}t^{2}+2 \ u \ at \\\\v^{2}=u^{2}+2a(\frac{1}{2}at^{2}+ut) \ taking \ 2a \ as \ common \ \\\\Now \ we \ know \ that s=\frac{1}{2}at^{2}+ut\\\\putting \ value \ of s \ here\\\\v^{2}=u^{2}+2as$