Question

Goodie morni...
Please solve it...
Urgently required......​

Answer 1

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Volume of plastic balloon= 15 m3

Mass of empty balloon = 7.15 kg Density of hydrogen=0.09 kgm-3

Density of air= 1.3 kgm 3

(i) Mass of hydrogen in the balloon= Volume of balloon x Density of hydrogen Mass of hydrogen in the balloon=

(15 x 0.09)kg

= 1.35kg

(ii) Mass of hydrogen and balloon Mass of empty balloon + Mass of hydrogen in the balloon

Mass of hydrogen balloon = [7.15+ 1.35) =

kg = 8.5 kg

(iii) Given mass of equipment= x Total mass of hydrogen, balloon and equipment

= (8.5+ x) kg

(iv) Weight of air displaced by the

balloon = upthrust = Volume of balloon x density of air x g

Mass of air displaced= Volume of balloon x density of air

= 15 x 1.3 = 19.5 kg

(v) Using the law of floatation,

Mass of air displaced 3 Total mass of hydrogen, balloon and equipment or, 19.5 = 8.5 + x

or, x=11 kg

Thus, mass of the equipment 11 kg

Answer 2

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a weather forecasting plastic balloon of volume of an equipment carried by by the the balloon is treatable compared to its own volume the mass of empty balloon alone is 7.15 kg the balloon is floating in in air of density 1.3 kg m·³

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Volume of plastic balloon= 15 m3

Mass of empty balloon = 7.15 kg Density of hydrogen=0.09 kgm-3

Density of air= 1.3 kgm 3

(i) Mass of hydrogen in the balloon= Volume of balloon x Density of hydrogen Mass of hydrogen in the balloon=

(15 x 0.09)kg= 1.35kg

(ii) Mass of hydrogen and balloon Mass of empty balloon + Mass of hydrogen in the balloon

Mass of hydrogen balloon = [7.15+ 1.35) = kg= 8.5kg

(iii) Given mass of equipment= x Total mass of hydrogen, balloon and equipment= (8.5+ x) kg

(iv) Weight of air displaced by theballoon = upthrust = Volume of balloon x density of air x g

Mass of air displaced= Volume of balloon x density of air= 15 x 1.3 = 19.5 kg

(v) Using the law of floatation,Mass of air displaced 3 Total mass of hydrogen, balloon and equipment or, 19.5 = 8.5 + xor, x=11 kg

Thus, mass of the equipment 11 kg