Google √1-cos²x/since+√1-sin²x/cos x
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sin²x + cos²x = 1
So √(1-cos²x) = sin x and √(1-sin²x) = cos x
So √1-cos²x/since+√1-sin²x/cos x = sin x/sin x + cos x/cos x = 1 + 1 = 2
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