CBSE BOARD X, asked by kesarapuprasad1424, 1 year ago

Gopal walks 20 m North. Then he turns right and walks 30 m. Then he turns right and walks 35 m. Again he turns left and walks 15 m. Then he again turns left and walks 15 m. The shortest distance between his original position and final one is

Answers

Answered by mehrin20
3

Gopal has walked 45m from its initial position

Answered by Agastya0606
10

Answer:

45 m

Explanation:

Gopal walks 20 m North. After that , he turns right and walks 30 m. And then he turns right and walks 35 m. Again he turns

left and walks 15 m. Then he again turns left and walks 15 m.  

The pictorial representation of the said question is given below:

                 30m

             _________

             |                   |

20m N  |                  |

              |                  |

             O       35 m |          | E    

                                 |          |15 m

                                 |          |

                                 |_____|

                                   15m

So, let us assume the starting point as O, and ending point as E, by the picture given, we can calculate, the shortest distance between initial and final point.

Therefore, The shortest distance would be 30m + 15 m = 45m

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