Question

Gopal walks from his house at a speed of 3 km/hr and reaches his school 5 minutes late If he walks at 5 km/hr .he reaches his school 5 minutes early. The distance of the school from his house is.​

Answer 1

Answer:

Step-by-step explanation:

Let the actual time be 't'

and distance be x

Now according to first condition, we have

4

x

​

=t+

60

5

​

And according to Second condition, we have

5

x

​

=t−

60

10

​

60x=4t+20

60x=5t−50

Subtracting equation 1 from 2, we have

0=t−70

∴t=70

Putting the value of t we get x=5km

Answer 2

Answer:

The distance of the school from his house = 5km

Step-by-step explanation:

$\ggg \underline{\bold{Given:-}}$

Gopi walks from is house at a speed of = 3km/hr

Gopi reaches his school in = 5 minutes

If Gopi walks from is house = 5km/hr

Then,he reaches his school = 5 minutes early

$\ggg \underline{\bold{Solution:-}}$

Let the actual time be x and distance be y

According to first condition, we have,

$\frac{y}{4}=x+\frac{5}{60}$

$60y = 4x +20$

And according to Second condition, we have

$\frac{y}{5} = x-\frac{10}{60}$

$60y = 5x-50$

Now,

$+\:60y=4x+20$

$-\:60y=5x-50$

______________

   0  =   x  - 30

______________

$0 =x-30$

$x = 30$

Putting the value of x we get y= 5km

The distance of the school from his house = 5km