Math, asked by monu949, 8 months ago

gopi purchased 35 erasers and some sharpners price of sharpner is twice that of an eraser instead, if she had bought as many sharpners as the no of erasers that he bought and vice versa , his total expenditure would be 20%more hoe many sharpners did he buy​

Answers

Answered by bkpaf225
2

Answer: Cost of erasers =2 6/7

Cost of sharpeners =1 3/7

Step-by-step explanation:

Answered by dikshaagarwal4442
0

Answer:

The number of sharpeners he bought is 26.

Step-by-step explanation:

Suppose Gopi bought 35 erasers, each of price 'r' and 'n' sharpeners.

The price of each sharpener = 2 × price of each eraser = 2r

  • Initial price: Total price of erasers = 35r

       Total price of sharpeners = n × 2r = 2nr

        Total price of eraser and sharpeners = 35r + 2nr

  • Final price: No of sharpeners(n) = no of erasers = 35.

        Total price of eraser and sharpeners = 35r + 2(35)r = 105r

  • Percentage: Change in price = 105r - 35r - 2nr = 70r - 2nr

        Percentage change = \frac{change in price}{initial price} × 100% = \frac{70r - 2nr}{35r + 2nr} × 100%

                                                                             = \frac{70 - 2n}{35 + 2n} × 100%

        According to the given condition,  \frac{70 - 2n}{35 + 2n} × 100% = 20%

                                                                   \frac{70 - 2n}{35 + 2n} = \frac{20}{100}

                                                                    \frac{70 - 2n}{35 + 2n} = \frac{1}{5}

                                                                5(70 - 2n) = 35 + 2n

                                                                 350 - 10n = 35 + 2n

                                                                    12n = 350 - 35 = 315

                                                                      n = \frac{315}{12} = 26.25 ≈ 26

        The number of sharpeners he bought is 26.

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