Question

Gordon, June and Sushil share some sweets in the ratio 4:5:1. Gordon gets 36 more sweets than Sushil. How many sweets does June get?

Answer 1

Step-by-step explanation:

Given:-

Gordon, June and Sushil share some sweets in the ratio 4:5:1. Gordon gets 36 more sweets than Sushil.

To find:-

How many sweets does June get?

Solution:-

Given that

The ratio of shares of Gordon , June and Sushil

= 4:5:1

Let the sweets of Gordon be 4X

Let the sweets of June be 5X

Let the sweets of Sushil be X

Given that

Gordon gets 36 more sweets than Sushil.

Gordon sweets = Sushil sweets + 36

=> 4X = X+36

=> 4X-X = 36

=> 3X = 36

=> X= 36/3

=> X= 12

Sweets of Sushil = 12

Sweets of Gordon = 12+36 = 48

Sweets of June = 5×12 = 60

Answer:-

June got 60 sweets for the given problem.

Check:-

Their ratio = 48:60:12 = 4:5:1

Sweets of Sushil + 36

=> 12+36

=> 48

=> Sweets of Gordon

Verified the given relations