Math, asked by traga, 1 year ago

got 90 minus theta tan theta minus Cos 890 minus theta sec theta divided by sin 12 cos 1578 cos 75 + cos square 50 + 3 X 40 - theta divided by 10 15 10 37 10 53 10 75

Answers

Answered by greathelper24
0
cot (90-theta)* tan theta - cosec(90-theta) * sec theta =
tan theta * tan theta - sec theta * sec theta
= tan square theta - sec square theta = 1
upon
sin 12*cos 15*cos 78*cos 75 + cos square (180-theta)=
sin 12*cos15*sin12*sin
Answered by yatinarora2003
0

Answer:

What?????????????????

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