goutham has 33.33% more pencils than rahul has. by how much percent less pencils rahul has than that of goutham
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Answered by
23
Hi there!
Here's the answer:
• If A is by x% more than B, then B is less than that of A is 'S%'.
S%= [(100x/100+x)]%
where S% - indicates %shortness.
Now,
say
G- No. of Pencils with Goutham.
R - No. of pencils with Rahul
Given G>R by 33.33% [i.e., (1/3)%]
R<G by 'S%'
S%= [(100×33.33)/(100+33.33)]
S%= 24.99%
•°• R<G by 24.99%.
:)
hope it helps
Here's the answer:
• If A is by x% more than B, then B is less than that of A is 'S%'.
S%= [(100x/100+x)]%
where S% - indicates %shortness.
Now,
say
G- No. of Pencils with Goutham.
R - No. of pencils with Rahul
Given G>R by 33.33% [i.e., (1/3)%]
R<G by 'S%'
S%= [(100×33.33)/(100+33.33)]
S%= 24.99%
•°• R<G by 24.99%.
:)
hope it helps
viswacps:
thanks for your help
Answered by
2
You can use the above calculator for maths calculation....lol
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