Question

govinda usually leaves his home every day at 8 am and travels at a certain speed to reach office on time one day he travelled at 4/5 of the usual speed and hence arrived 22.5mum late how much tome daes g

Answer 1

Answer:

1.5 hr

Step-by-step explanation:

Let govinda usual speed = x km/hr

Reduced speed = 4x/5 km/hr

Time taken on usual day = D / x

Time taken on reduced speed =  D/(4x/5) = 5D/4x

5D/4x - D/x = 22.5/60

5D - 4D = 4x (22.5/60)

D = 22.5x/15

D = 1.5x

D/x = 1.5 hr