Question

grade 10th it's urgent

Answer 1

Given Equation is secθ + tanθ = x.

We know that sec²θ - tan²θ = 1 and a² - b² = (a + b)(a - b).

⇒ (secθ + tanθ)(secθ - tanθ) = 1

⇒ (x)(secθ - tanθ) = 1

⇒ (secθ - tanθ) = (1/x).

Hope it helps!