Question

grade 10th it's urgent

Answer 1

hey mate ... hey is ur answer
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Answer 2

cosec = 3x.....(1)
cot= 3/x...(2)

on Adding both (1)&(2),

cosec+cot= 3x+3/x
cosec+cot = 3(x+1/x)....(3)

on Subtracting (1)&(2),

cosec-cot = 3x-3/x
Again,. cosec-cot= 3(x-1/x)....(4)

Now, on multiplying (3)&(4),

(cosec)²-(cot)²= 9 [ (x²) - (1/x)² ]
cosec² - cot² = 9( x²- (1/x)²
1 =9(x²- (1/x)²
On MULTIPLYING both the sides by 3
3(x² - (1/x)²) = 1/9 × 3/1

= 1/3.....ANSWER