Math, asked by nidhi411, 1 year ago

grade 10th plz it's urgent

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Answers

Answered by Sreedu
1

Answer:


Step-by-step explanation:

Sec ¢ + tan ¢ + 1 = 0

Sec ¢ + tan ¢ = -1

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Answered by saanviy01
0

Answer:

-1

Step-by-step explanation:

sec A+ tan A+1 = 0

So...

sec A + tan A = -1

sec^2A - tan^2A = 1

(sec A+tan A)(sec A-tan A) = 1

sec A-tan A = 1/-1

sec A - tan A = -1

Hoping to be helpful....


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