grade 6 students were asked to arrange themselves in rows. If there are a total of 40 students, what is the minimum number of rows such that a row must have a maximum of 6 students
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Prime factories 40=2×2÷2×5.
40 has factors 1 2 4 5 8 10 20 40 = 8 factors giving value of r=rows. Number of columns =c=(40/r).
Other method ;
Distribute these 4 prime factors as rows × columns to form a rectangle as
2×20 20×2 4×10 10×4 8×5 5×8
Or Total 6 possible pairs of values as above assuming number of rows and columns is >=2.
However, if it is possible that r or c=1 allowed, then 2 more pairs of values 1,40 & 40,1 thus taking total possible values to (6+2)=8 pairs of values.
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