gradient of 5y+12x-60=0 step by step
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Anneong, Here is the ans
Step-by-step explanation:
Line l cuts the x-axis at P (a , 0) and Q (0 , b), where a and b are to be found out.
plugging y = 0 and x = a we get, 12a - 60 = 0
=> a = 5
plugging x = 0 and y = b we get, 5b - 60 = 0
=> b = 12
so, co-ordinates of P ≡ (5 , 0) and of Q ≡ (0 , 12) ------> (Ans)
2) slope of the line = -12/5 & point (0 , -2)
equation of requred line ; y - y1 = m (x - x1)
=> y + 2 = (-12/5) (x - 0)
=> 5y + 10 = -12x
=> 12 x + 5y + 10 = 0 ---------> (Ans)
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