Gram atoms of oxygen present in 128 grams of oxygen
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as molar mass of O atom =16g/mol
16g O atom =1 gram - atom O
128g „ „ = 128÷16 „ „ „
= 8 gram -atom O
16g O atom =1 gram - atom O
128g „ „ = 128÷16 „ „ „
= 8 gram -atom O
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