Math, asked by sanjeevkumar1070, 1 month ago

Grandma Millie is shrinking! Her height decreases by1/4cm} each year



What is her total change in height over 3 years

Answers

Answered by 12thpáìn
2

Given

  • height decreases by 1/4 cm each year.

To Find

  • Height Decrease in 3 year's.

Solution

\sf Height ~~Decrease~~ in~~ 3~ year's.=  \dfrac{1}{4}  +  \dfrac{1}{4}  +  \dfrac{1}{4}

\sf Height ~~Decrease~~ in~~ 3~ year's.=  \dfrac{1 + 1 + 1}{4}

\sf Height ~~Decrease~~ in~~ 3~ year's.=  \dfrac{3}{4} cm \\  \\  \\

_Hope it helpful

Answered by Anonymous
2

Given

height decreases by 1/4 cm each year.

To Find

Height Decrease in 3 year's.

Solution

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.=

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 4

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 +

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 4

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 +

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 + 4

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 + 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 + 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 + 41

Solution\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{1}{4} + \dfrac{1}{4} + \dfrac{1}{4}Height Decrease in 3 year ′ s.= 41 + 41 + 41 \sf Height ~</strong>~<strong>Decrease~~ in~~ 3~ year's.= \dfrac{1 + 1 + 1}{4}Height  Decrease  in  3 year

′ s.=

′ s.= 4

′ s.= 41+1+1

′ s.= 41+1+1

′ s.= 41+1+1

′ s.= 41+1+1 [tex]\begin{gathered}\sf Height ~~Decrease~~ in~~ 3~ year's.= \dfrac{3}{4} cm \\ \\ \\ \end{gathered} [/tex]

\\ \\ \end{gathered} [/tex]Height Decrease in 3 year

s.=

4

3

cm

_Hope it helpful

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