Question

graph having variation of t-square with L .

Answer 1

finding the acceleration due to gravity

the time period of simple pendulum (I) and acceleration due to gravity (g), which is expressed by relation,

T=2π√l/g ----------(1)

for small amplitude oscillations,


T square= 4π square l/g
I.e;

g= 4πsquare l/t square-----------(2)
if we know the value of L and T, we can calculate the acceleration due to gravity , g at that place.

the l-t square graph

we can plot a graph between l and T2 square by taking l along the x axis and T2 along the y axis. The graph is a straight line.(graph is given above)

from the graph,


l/t square= AB/BC=---------cm square

g= 4π square (AB/BC)




ALRIGHT
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Answer 2

Answer:

Explanation:

the time period of simple pendulum (I) and acceleration due to gravity (g), which is expressed by relation,

T=2π√l/g ----------(1)

for small amplitude oscillations,

T square= 4π square l/g

I.e;

g= 4πsquare l/t square-----------(2)

if we know the value of L and T, we can calculate the acceleration due to gravity , g at that place.

the l-t square graph

we can plot a graph between l and T2 square by taking l along the x axis and T2 along the y axis. The graph is a straight line.(graph is given above

from the graph,

l/t square= AB/BC=---------cm square

g= 4π square (AB/BC)

ALRIGHT

PLEASE SELECT AS BRAINIEST ANSWER