graph of the equation ax+by+c=0 , a*0, 6*0, cuts x axis and y axis respectively at points
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Answered by
77
Given : Graph of the linear equation ax + by + c = 0 a is not equal to 0
To Find : Graph cuts x axis and y axis respectively at the point
Solution:
ax + by + c = 0
cuts x axis => y = 0
Substitute y = 0
=> ax + b(0) + c = 0
=> ax + c = 0
=> x = - c/a
cuts y axis => x = 0
Substitute x = 0
=> ax(0) + by + c = 0
=> by + c = 0
=> y = - c/b
cuts x axis at ( - c/a , 0) and y axis at ( 0 , - c/b )
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Answered by
10
Answer:
(-ca,0),(0,-cb)
is the answer
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