Math, asked by Anonymous, 1 month ago

Graph of the functions, cos (1/x) and sin (1/x) are weird because of the number of oscillations of the curve near the interval [-1 , 1 ].

Can you justify the reason for this densely oscillated curve?​

Answers

Answered by senboni123456
11

Step-by-step explanation:

The given functions works well in any number \in[-1,1], except at x=0, due to the following reason:

 \bullet \:  \sf{ \blue{As, \:  \:x \to0 ,  the \: \:  graphs \: \:  of \:  \: the \:  \: given \:  \: functions \:  \:  approaches \:  \: its \:  \: limiting \:  \: value.}}

Consider,

 \sf{ \lim_{x \to0} \bigg \{ sin \bigg( \dfrac{1}{x} \bigg)\bigg \} } \\

 \sf{ = sin ( \infty ) } \\

This implies, the graph could take any value \in[-1,1]. Even same value can also repeat many times because we can't say what value it will take.

Since \sf{sin(\infty)} is not defined, but it can't exceed the range of sine function.

\boxed{ \sf{\color{cyan} Hence,\:\:it\,\,oscillates\,\,in\,\,between\,\,[-1,1] } }

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