Question

graph the function y=-2x+1 using inputs of -1, 0, 1, and 2
Pls show steps

Answer 1

Answer:

The points which are plot in the graph are (-1,3),(0,1),(1,-1),(2,-3)

Step-by-step explanation:

y = - 2 x + 1

If x = -1 , y = -2 ( -1 ) + 1 = 2 + 1. = 3

If x = 0 , y = -2 ( 0 ) + 1 = 0 + 1 = 1

If x = 1 , y = -2 ( 1 ) + 1 = -2 + 1 = -1

If x = 2 , y = -2 ( 2 ) + 1 = -4 + 1 = -3

Answer 2

$\large\underline{\sf{Solution-}}$

Given that

$\rm :\longmapsto\:y = 2x + 1$

1. Substituting x = - 1 in the given equation, we get

$\rm :\longmapsto\:y = 2 \times ( - 1)+ 1$

$\rm :\longmapsto\:y = - 2+ 1$

$\bf\implies \:y = - \: 1$

2. Substituting x = 0 in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 0 + 1$

$\rm :\longmapsto\:y = 0 + 1$

$\bf\implies \:y = 1$

3. Substituting x = 1 in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 1 + 1$

$\rm :\longmapsto\:y = 2 + 1$

$\bf\implies \:y = 3$

4. Substituting x = 2 in the given equation, we get

$\rm :\longmapsto\:y = 2 \times 2 + 1$

$\rm :\longmapsto\:y = 4 + 1$

$\bf\implies \:y = 5$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf - 1 & \sf - 1 \\ \\ \sf 0 & \sf 1 \\ \\ \sf 1 & \sf 3\\ \\ \sf 2 & \sf 5 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points (- 1 , - 1), (0 , 1), (1, 3) & (2 , 0)

➢ See the attachment graph