Question

graph the quadratic equation and state their nature of solutions. x2+x-12 = 0​

Answer 1

Answer:

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Step-by-step explanation:

The given quadratic equation is x  

2

+x−12=0.  

Let y=x  

2

+x−12, when we substitute different values of x in the equation y=x  

2

+x−12 then value of y changes accordingly.

When x=0 then

y=(0)  

2

+0−12=0+0−12=−12

The point is (0,−12)

When x=3 then

y=(3)  

2

+3−12=9+3−12=0

The point is (3,0)

When x=−4 then

y=(−4)  

2

−4−12=16−4−12=0

The point is (−4,0)

Therefore, the coordinates are (0,−12), (3,0) and (−4,0) and the graph of the quadratic equation y=x  

2

+x−12 is as shown above.

Hence, from above graph, we get that x=−4 or x=3.

Answer 2

Answer:

x2+x-12=0

2×=0-12÷2

×=-6÷2

×=-3