Question

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f'(-1)=0 , f''(-1) > 0, f(-1)=-5

f' (7) = 0, f''(7) < ) , f(7)=10

f''(3)=0, f'(3)=2​

Answer 1

Answer:

f:[−7,0]→R

f(−7)=−3

f

′

(x)≤2

Integrate →

f(x)≤2x+c

Put x=−7

f(−7)≤−14+c

c≥14−3

c≥11

f(x)≤2x+11

f(−1)≤9

f(0)≤11

f(0)+f(−1)≤20

[−∞,20]

option -(2)

Step-by-step explanation:

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