Question

Graphically
3x + 6y = 3900 (1)
x = 100,300
Y = 600,500
x + 3y = 1300 (2)
x = 100,400
Y = 400,300​

Answer 1

Answer:

given,

Zeroes are 1/2+2√3 and 1/2-2√3

sum of zeroes = 1/2+2√3 + 1/2-2√3

= 1/2 + 1/2

= 1

product of zeroes = 1/2+2√3 x 1/2-2√3

= [ 1/2 ] ² - [ 2√3 ]²

= 1/4 - 12

= 1/4 - 48 / 4

= -47 /4

Quadratic equation

x² - [ sum of zeroes ]x + product of zeroes

=x² - x + -47/4............

tex] \begin{lgathered}\tt \implies \: (25 - x) {}^{2} = (x) {}^{2} + (5) {}^{2} \\ \tt \implies625 - 50 + x {}^{2} = x {}^{2} + 25 \\ \tt \implies - 50xSteps:

1) Draw a line segment AB of length 9.3 units.

2) Extend the line by 1 unit more such that BC=1 unit .

3) Find the midpoint of AC.

4) Draw a line BD perpendicular to AB and let it intersect the semicircle at point D.

5) Draw an arc DE such that BE=BD.

Therefore, BE=

9.3

units