Graphically derive the equation for position-velocity relation of an object accelerating uniformly. If the object accelerates uniformly from 18 kmh-1 to 36 kmh-1 in 5sec , calculate its acceleration and the distance covered by the object in that time.?
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Acceleration=TimeChange in Velocity
Change in Velocity = 36−18=18km/h=5m/s
Time=5 Seconds
Acceleration =55=1m/s2
Equation of motion can be given as:
s=ut+(21)at2
u=18km/h=5m/s
t=5s
a=1m/s2
s=(5×5)+(21×1×5×5)
s=25+12.5
s=37.5m
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