Graphically solve the system of linear inequalities :
4x + 3y ≤ 60 , 2x − y ≥ 0 , x ≥ 3 , x ≥ 0 , y ≥ 0.
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4x+3y≤60 .......(1)
y≥2x .....(2)
x≥3 .....(3)
The graph of the lines, 4x+3y=60,y=2x,x=3, are drawn in the figure below.
Inequality (1) represents the region below the line, 4x+3y=60 ( including the line 4x+3y=60). Inequality (2) represents the region above the line, y=2x ( including the line y=2x). Inequality (3) represents the region on the right hand side of the line, x=3 ( including the line x=3).
Hence, the solution of the given system of the linear inequalities is represented by the common shaded region including the points on the respective lines as follows.
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