Question

graphically that the maximum or minimum
z=5x1 + 3X2
subject to the constraints
x + x2 <6​

Answer 1

Answer:

methodMaximize Z = 5X1 + 3X2Subject to constraints2X1 + X2 ≤ 1000X1 ≤ 400X1 ≤ 700X1, X2 ≥ 0Solution:The first constraint 2X1 + X2 ≤ 1000 can be represented as follows.We set 2X1 + X2 = 1000When X1 = 0 in the above constraint, we get,2 x 0 + X2 = 1000X2 = 1000Similarly when X2 = 0 in the above constraint, we get,2X1 + 0 = 1000X1 = 1000/2 = 500The second constraint X1 ≤ 400 can be represented as follows,We set X1 = 400The third constraint X2 ≤ 700 can be represented as follows,We set X2 = 700

12The constraints are shown plotted in the above figurePointX1X2Z = 5X1 +3X20000A0700Z = 5 x 0 + 3 x 700 = 2,100B150700Z = 5 x 150 + 3 x 700 = 2,850*MaximumC400200Z = 5 x 400 + 3 x 200 = 2,600D4000Z = 5 x 400 + 3 x 0 = 2,000The Maximum profit is at point BWhen X1 = 150 and X2 = 700Z = 2850Example 2.Solve the following LPP by graphical methodMaximize Z = 400X1 + 200X2Subject to constraints18X1 + 3X2 ≤ 8009X1 + 4X2 ≤ 600X2 ≤ 150X1, X2 ≥ 0Solution:The first constraint 18X1 + 3X2 ≤ 800 can be represented as follows.We set 18X1 + 3X2 = 800When X1 = 0 in the above constraint, we get,18 x 0 + 3X2 = 800X2 = 800/3 = 266.67Similarly when X2 = 0 in the above constraint, we get,18X1 + 3 x 0 = 800X1 = 800/18 = 44.44The second constraint 9X1 + 4X2 ≤ 600can be represented as follows,We set 9X1 + 4X2 = 600When X1 = 0 in the above constraint, we get,9 x 0 + 4X2 = 600X2 = 600/4 = 150Similarly when X2 = 0 in the above constraint, we get,9X1 + 4 x 0 = 600X1 = 600/9 = 66.67The third constraint X2 ≤ 150 can be represented as follows,We set X2 = 150

Answer 2

Answer:

anbhxjxkaokajshdjfjdjjxnabsbbzbsbsbsbdbbdbdbf