Question

graphs of sinx and 2sinx are of same shape but maximumheight of the graph of sinx is
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Answer 1

Maximum height of the graph of sinx=1

Step-by-step explanation:

Let

$y=sinx$

Substitute x=0 degree

$y=sin=0$

Substitute x=90 degree

$y=sin90^{\circ}$

$y=1$

Because $sin90^{\circ}=1$

Suppose , $y'=2sinx$

Substitute x=0 degree

$y'=2sin0=0$

Substitute x=90 degree

$y=2sin90^{\circ}=2\times 1=2$

Maximum value of sinx =1

Maximum value of 2 sinx=2

Minimum value of sinx and 2 sinx=0

Hence, maximum height of the graph of sinx=1

#Learn more:

https://brainly.in/question/12396906:Answered by Ashokaparida

Answer 2

Given : 4. The maximum height of the graph of sin 2xis ___________ . It is at2x = _________ .

5. At x = ________, sin x = 0, at x = _______, sin 2x = 0 and at x = ________,sin2x = 0.

6. In the interval [0, π], graphs of sin x, 2 sin x and sin 2x are _______ x - axes and some portion of the graph of sin 2x lies _______ x-axes.

7. Graphs of sin x and sin 2x intersect at x = _______ in the interval (0, π)

To Find : Fill in the Blanks

Solution:

1. Graphs of sin x and 2 sin x are of same shape but the maximum height of the  graph of sin x is __2______ the maximum height of the graph of Sinx is 1__________.

2. The maximum height of the graph of sin 2x is ____2_______. It is at x =

__π/4_______.

3. The maximum height of the graph of 2 sin x is ____2_______ . It is at x =

__π/2_______ .

4. The maximum height of the graph of sin 2x is ___1__ . It is at 2x =  π/2

5. At x = __0 ______, sin x = 0, at x = __0___, sin 2x = 0 and at x = ___π/2_____,sin2x = 0.

6. In the interval [0, π], graphs of sin x, 2 sin x and sin 2x are _above______ x - axes and some portion of the graph of sin 2x lies _below______ x-axes.

7. Graphs of sin x and sin 2x intersect at x = __π/3_____ in the interval (0, π)

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