Math, asked by sujitkumardas886, 3 months ago

graslande an +35
the future. The allotment officer is trying to come up with a method to calculate fair division of funds
across various affected families so that the fund amount and amount received per family can be easily
adjusted based on daily revised numbers. The total fund allotted is formulated by the officer is(x + 6x +
20x + 9). The officer has also divided the fund equally among families of the village and each family
receives an amount of ( x + 2x + 2). After distribution, an amount of (10x + 1) is left.
(i) How many families are there in the village?
(a) x + 4
(b) x-3
(c) x-4
(d) x + 3
(ii) If an amount of Rs 1911 is left after distribution, what is value of x?
(a) 190
(b) 290
(c) 191
(d) 291
(iii) How much amount does each family receive?
(a) 24490
(b) 34860
(c) 22540
(d) 36865
(iv) What is the amount of fund allocated?
(a) Rs 7272759 (b) Rs 7572681 (c) Rs 6972846 (d) Rs 8274888
(v) How many families are there in the village?
(a) 191
(b) 98
(C) 187
(d) 195
rve International Circuit are analysing last​

Answers

Answered by amitnrw
11

Given  : The total fund allotted is formulated by the officer is x³ + 6x² + 20x + 9

divided the fund equally among families of the village

each family receives an amount of x² + 2x + 2  and After distribution, an amount of 10x+ 1  is left

To Find : How many families are there in the village

an amount of ₹1911 is left after distribution, what is value of x

How much amount does each family receive

How many families are there in the village

Solution :

                              x + 4

    x² + 2x + 2   _|  x³ + 6x² + 20x + 9 |_

                                x³ + 2x² + 2x

                               ___________

                                       4x² + 18x + 9

                                       4x² + 8x + 8

                               ________________

                                                 10x + 1

x + 4  families are there in the village

10x + 1 = 1911

=> 10x = 1910

=> x = 191

amount each family receive         x² + 2x + 2

= 191²  + 2(191) + 2

= 36865

amount of fund allocated  = x³ + 6x² + 20x + 9

191³ + 6(191²) + 20(191)+ 9

= 71,90,586

families are there in the village  = 191 + 4 = 195

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Answered by kusumpatil942
1

Answer:

families in the village is = 195

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