Question

Gravel is dropped on a conveyor belt at the rate of 2kg/s.The extra force required to keep the best moving at 3m/s is​

Answer 1

Answer:

dt

dm

=2kg/s

Velocity,v=3m/s

To find:

Extra force required to keep the belt moving at velocity 3 m/s

Solution:

\frac{dm}{dt}=2kg/s

dt

dm

=2kg/s

v=3m/s

We know that

Force generated due to falling gravel in a conveyor belt

F=\frac{dm}{dt}\times vF=

dt

dm

×v

Where v=Velocity

Using the formula

Extra force required to keep the belt moving at speed 3 m/s=2\times 3=6 N2×3=6N