Question

gravel is dropped on a conveyor belt at the rate of 2kgs the extra force required to keep the belt moving at 3ms is​

Answer 1

Answer:

dm/dt =2kg/s

Velocity,v=3m/s

To find:

Extra force required to keep the belt moving at velocity 3 m/s

Solution:

F=dm/dt×v

Force generated due to falling gravel in a conveyer belt=dm/dt ×v

Where v=Velocity

Using the formula

Extra force required to keep the belt moving at speed

=3×2=6N

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Answer 2

upper answer is correct answer......