Question

Gravels are dropped on a conveyers belt at the rate of 0.5 kg per sec.the extra force required newtons to keep the belt moving at 2 m per sec is?

Answer 1

here v is constant hence dv/dt is 0

dm/dt= 0.5 kg/sec, v=2m/s

hence extra force required= v*dm/dt = 2*0.5 = 1N
here v is constant hence dv/dt is 0

dm/dt= 0.5 kg/sec, v=2m/s

hence extra force required= v*dm/dt = 2*0.5 = 1N