Physics, asked by annzel535, 10 months ago

Gravitaional field intensity for a point inside solid sphere

Answers

Answered by pratapscience
0

Answer:

Always zero.

Explanation:

Gravitational field intensity inside a solid sphere. It is quite easy to derive the gravitational field intensity at a point within a solid sphere. However, the result is quite surprising. The field intensity at any point within a solid sphere is zero.

Answered by Anonymous
52

Answer:

The strength of the gravitational field is known as gravitational field intensity. It is the gravitational force acting on a unit test mass.

Eg = F/m

Or, Eg = – [GMm/r2]/m r^

⇒ Gravitational Field Intensity (Eg) = – GM/r2 r^

Where r^ represents the unit vector along the radial direction, r⃗ =xi^+yj^+zk^ represents the position vector of the test mass from the source mass.

The gravitational field intensity depends only upon the source mass and the distance of unit test mass from the source mass.

The unit of gravitational field intensity is N/kg.

The dimensional formula is given by [M0L1T-2].

The dimensional formula of gravitational field intensity is identical to the acceleration (preferably we call it as acceleration due to gravity from the view of gravitation).

Explanation:

The superposition principle extends to gravitational field intensities as,

E = E1 + E2 + E3 + . . . . . . . + En

Where, E1, E2, E3, . . . . . En are the gravitational field intensities at a point due to n particles in a system.

In a system, the mass is always distributed in two different ways:

Discrete mass distribution

Continuous mass distribution

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