Question

Gravitational field and the gravitational potential at the surface of the moon. given the mass of the moon, M=7.34×10²² kg, radius of the moon, R=1.74×10⁶ m and the gravitational constant, G=6.67×10-¹¹ Nm² Kg-².​

Answer 1

Explanation:

Correct option is

B

1.87×106m

gm=R2GM

1.4=R2(6.667×10−11)(7.34×1022)

R=1.46.667×10−11(7.34×1022)

=34.95×1011=1.87×106m

Answer 2

Answer:1.63 m/s^2

Explanation:

we know that ,

=>g = G x M/r^2

wHere,

=>Gravitational constant, G = 6.67 x 10^-11 Nm^2/kg^2

=>Mass of Moon, M =7.34 x 10^22kg

=> Radius of Moon, r =1.74 x 10^5

So, g = 6.67 x 10^-11 x 7.34 x 10^22/(1.74 x 10^5)^2

=> g = 1.63 m/s