Question

gravitational force between two objects is F. How will the force change when the distance between them is reduced to 1/4 th ?
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Answer 1

Explanation:

$gravitational \: force \: = \frac{gravitational \: constant \times mass \: of \: object \: 1 \times mass \: of \: object \: 2}{ {distance}^{2} }$

If distance is reduced by 1/4th, the actual decrease in distance will be:

${ (\frac{1}{4} )}^{2} = \frac{1}{16}$

The value is squared since the formula has a squared value of distance.

When distance decreases, the force increases since these values are inversely proportional to each other. The gravitational constant and masses are a constant value.

Thus force increases 16 times.