Question

Gravitational force between two point masses m and M separated by a distance r is F. Now if the distance between them is halved, the force between them becomes​

Answer 1

Answer:

. If r is the distance between two point masses m and M, then the gravitational force on m due to mass M is F = GMm/r

2

. Since the gravitational force between two point masses is independent of the presence of other masses, so if a point mass 3m is placed next to m, the force on M due to m is F=

r

2

GMm

b. Total force on the body of mass M is F, i.e.,

F=

r

2

GM×(m+3m)

=

r

2

4GMm

=4F.

Explanation:

please mark me as a Brainliest

Answer 2

Given :

Gravitational force between two point masses m and M separated by a distance r is F.

To Find :

The force between the masses m and M when the distance between them is halved.

Solution :

Gravitational force (F) when the distance between m and M is 'r' (F) = $\frac{GMm}{r^{2} }$

Gravitational Force ($F^{'}$) when the distance between m and M is halved  

= $\frac{GMm}{(\frac{r}{2} )^{2} }$

= $\frac{4GMm}{r^{2} }$ = 4F

∴   $F^{'}$ = 4F

∴ The Gravitational Force ($F^{'}$) when the distance between m and M is halved is four times of the force (F) when the distance between m and M is r.