Physics, asked by prakashpatil10, 1 month ago

Gravitational force on the surface of moon is only 1/6 as strong as gravitational force on the earth. What is
the weight in newtons of a 10 kg object on the moon and on the earth?​

Answers

Answered by s123391
7

Answer:

16.3n

Explanation:

Mass of the object, m=10 kg

Acceleration due to gravity at earth, g  

e

​  

=9.8 ms  

−2

 

∴ Weight of the object on earth, W=mg  

e

​  

=10×9.8=98 N

Acceleration due to gravity at moon, g  

m

​  

=  

6

1

​  

×9.8=1.63  ms  

−2

 

∴ Weight of the object on moon, W=mg  

m

​  

=10×1.63=16.3 N

Answered by Evilhalt
669

  \large\sf \underline{ \color{blue}{Question}}

Gravitational force on the surface of moon is only 1/6 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?

 \sf \large{ \color{blue}{AnsWer}}

we know that , the acceleration due to gravity on the surface of earth is 9.8 m/s . so the acceleration due to gravity on the surface of moon will be 1/6 of this value .

 \sf{ \color{darkblue}{that \: is \: 9.8 \times  \frac{1}{6}  {ms}^{2} }}

(I) calculation of weight on the moon

  \implies\sf{ \color{darkblue}{mass \: of \: object \: (m) \:  = 10kg}}

 \implies \sf{ \color{darkblue}{acceleration \: (g) \:  = 9.8 \times  \frac{1}{6} }}

Now , weight of object ,

 \implies \sf{ \color{darkblue}{w = m \times g}}

 \implies \sf{ \color{darkblue}{10 \times 9.8}}

 \implies \sf{ \color{darkblue}{16.3 \: newton}}

(ii) calculation of weight on the earth

  \implies\sf{ \color{darkblue}{mass \: of \: object \: (m) \:  = 10kg}}

 \implies \sf{ \color{darkblue}{acceleration \: (g)  = 9.8}}

Now , weight of object ,

 \implies \sf{ \color{darkblue}{w = m \times g}}

 \implies \sf{ \color{darkblue}{98 \: newton}}

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