Question

Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth what is the weight in Newton of a 10 kg object on the moon and all the earth?

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Answer 1

$\huge{ \mathtt{GivEn:-}}$

• Mass of the object = 10kg

$\large{ \mathtt{ \underline{CoNstant \: valuE:-}}}$

• Acceleration due to gravity on the surface of the earth = 9.8m/s².

$\large{ \mathtt{ \underline{Need \: tO \: find:-}}}$

• Weight of the object on the moon and on the earth in Newton of the mass 10 kg.

$\large{ \mathtt{FoRmula \: usEd:-}}$

• Weight = mass × gravity

$\large{ \mathtt{ \underline{ \red{ \: Explaination:-}}}}$

As it given that,

Acceleration due to gravity on the surface of the Earth = 9.8 m/s².

Therefore,

The acceleration due to gravity on the surface of the moon will be 1/6th of this value.

$\large{ \boxed{ \purple{ \implies{9.8 \times \frac{1}{6} {ms}^{ - 2} }}}}$

As we know that,

Mass = 10 kg

Gravity on the surface of the moon = 9.8×1/6 m/s²

$\small{ \mathtt{ \underline{\bold{CalculaTinG \: wEighT \: oN \: thE \: moOn;}}}}$

Weight = mass × gravity

$\large{ \implies{10 \times 9.8 \times \frac{1}{6} }} \\ \large \implies \large{ \boxed{ \pink{ \mathtt{16.3 \: N }}}}$

$\huge{ \mathrm{ \red{NOW,}}}$

As we know that,

Mass = 10 kg

Gravity on the surface of the earth = 9.8m/s²

$\small{ \mathtt{ \underline{\bold{CalculaTinG \: wEighT \: oN \: thE \: eArth;}}}}$

Weight = mass × gravity

$\large{ \implies{10 \times 9.8 }} \\ \large \implies \large{ \boxed{ \orange{ \mathtt{98 \: N }}}}$

Answer 2

Answer:

98N and 16.3N

Step-by-step explanation:

mass of object on moon = 10 kg

mass of object on earth = 10 kg

weight of object on earth= 10 * 9.8 = 98N

weight of object n moon = 1/6 * 98 =16.3N