Question

Gravity acceleration at height h from the surface of earth

Answer 1

Answer:

answer is:

Explanation:

g=GM/R^2 at surface

at h height

gn=GM/(R+h)^2=GM/R^2(1+h/R)^2

so gn=g/(1+h/R)^2

if h<<R

then

(1+h/R)^-2=1-2h/R

so now gn=g(1-2h/R)

Answer 2

Answer:

Near Earth's surface, gravitational acceleration is approximately 9.8 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.8 metres per second every second.