Question

grd 9
please correct answer fast​

Answer 1

Explanation:

Information given:

Oxygen=0.096g

Boron= 0.144g

Total composition= 0.24g

Answer:

Percentage composition=

$percentage \: composition \: in \: compound = \frac{composition \: of \: element}{total \: composition} \times 100$

Therefore, percentage composition of oxygen= 0.096/0.24 × 100

= 40%

percentage composition of boron= 0.144/0.24 × 100

= 60%

Hence, de, the composition of oxygen is 40% and composition of boron is 60%