Question

GRE scores are normally distributed with mean 500 and S.D. 100. Find the probability that a randomly selected GRE score is greater than 620. (Given that A(1.2)=0.3849)​

Answer 1

Answer:

For normal distribution , P(x)=1/(sigmasqrt(2pi))e^(-(x-mu)^2/(2sigma^2))

The scores on standardised admissions test are normally distributed with a mean of 500500

Mean (μ)=500

standard deviation(σ)=100

Probability that score lies between 400 and 600 i.e, P(400

For standard normal distribution curve

Z=(x-μ)/σ

(400-500)/100<(x-μ)/σ<(600-500)/100

-1