Math, asked by krishna27709, 3 months ago

greatest 4 digit no exactly dividible by 31

Answers

Answered by RvChaudharY50
4

Given :- greatest 4 digit no exactly divisible by 31 ?

Solution :-

we know that,

  • Greatest four digit number is = 9999

so, dividing 9999 by 31 we get,

31 ) 9999 ( 322

93

69

62

79

62

17

we get,

→ Quotient = 322

→ Remainder = 17

then, we can conclude that, if we subtract remainder 17 from 9999 it will be perfectly divisible by 31 .

therefore,

→ Required number = 9999 - 17 = 9982 (Ans.)

Hence, the greatest 4 digit no exactly divisible by 31 is 9982 .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

p...

https://brainly.in/question/40043888

Answered by PADMINI
3

Given:

Find the greatest 4 digit number exactly divisible by 31

Solution:

The greatest four-digit number is 9999

Divide the greatest four-digit number by 31

31)  9999 (322

 -    93

   _______

         69

    -    62

   _______

           79

        -  62

   _______

            17

When we divide 9999 by 31, we get 17 as the remainder.

Now, subtract the remainder from the greatest four-digit number.

=> 9999 - 17

=> 9982

Hence, the greatest four-digit number exactly divisible by 31 is 9982

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