greatest no. of six digits divisible by 15,24,36
Answers
Answered by
7
LCM of 15 , 24 and 36
15 = 3×5
24= 2×2×2×3
36=2×2×3×3
LCM = 2×2×2×3×3×5 =360
now, greatest 6 digit number is 999999
greatest 6 digit number divisible by 360 is
360)999999(277
720
-
2799
2520
-
2799
2520
-
2799
2520
-
279 (remainder)
so the number will be (999999-279) = 999720
15 = 3×5
24= 2×2×2×3
36=2×2×3×3
LCM = 2×2×2×3×3×5 =360
now, greatest 6 digit number is 999999
greatest 6 digit number divisible by 360 is
360)999999(277
720
-
2799
2520
-
2799
2520
-
2799
2520
-
279 (remainder)
so the number will be (999999-279) = 999720
Answered by
0
Answer:
999720
To find the greatest six digits number exactly divisible by 24, 15 and 36. We have to subtract 279 from 999999. Hence, The greatest number of 6 digits exactly divisible by 24, 15 and 36 is 999720.
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