Question

Greatest no. that exactly divides 396 but divides 619 to give remainder 7

Answer 1

when divides 619 should give a remainder of 7

then 619 - 7 = 612

612 will be the number that will be completely divisible

now

396 = 3 x 3 x 2 x 2 x 11

612 = 3 x 3 x 2 x 2 x 17

HCF = 3 x 3 x 2 x 2 = 36

36 should be the number to divide 396 completely and when divides 619 will leaves a remainder of 7

Answer 2

Answer:

36

Step-by-step explanation:

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