greatest number of six digits which is exactly divisible by 27,45,60,72 and 90
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LCM of 27, 45, 60, 72, and 90 = 1080
greatest number of 6 digits = 999999
when 999999 is divided by 1080, the remainder is 999
therefore the greatest number of six digits which is exactly divisible by 27, 45, 60, 72 & 90 is ( 999999 - 999 ) = 999000
So your answer is 999000
Hope this helps you...
please mark my answer as brainliest...
greatest number of 6 digits = 999999
when 999999 is divided by 1080, the remainder is 999
therefore the greatest number of six digits which is exactly divisible by 27, 45, 60, 72 & 90 is ( 999999 - 999 ) = 999000
So your answer is 999000
Hope this helps you...
please mark my answer as brainliest...
baqir13:
ohk
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