Question

green
93. In pea plants, the allele for round seeds (R) is dominant to the allele for
wrinkled seeds (r) and the allele for yellow seeds (Y) is dominant to the allele for
seeds (y). A doubly heterozygous, round, yellow-seeded plant is crossed
with a green, wrinkled-seeded plant.
What percentage of the Fi generation are recombinants?
R
a. 0%
b. 25%
c. 50%
d. 75%
e. 100%​

Answer 1

Explanation:

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

So, the correct option is ‘9:3:3:1’.